PRACTICE PROBLEM 2 :(24-1 to 31-1) :'L' Pattern

======================================================================== #include<stdio.h>

void main()

{

int i,j;

int r,c;

scanf("%d %d",&r,&c);

char a[r][c];

for(i=0;i<r;i++)

for(j=0;j<c;j++)

scanf(" %c",&a[i][j]);

int check=0;

for(i=0;i<r;i++)

{

for(j=0;j<c;j++)

{

int x,y;

x=i;

y=j;

int up,right;

up=0;

right=0;

//ANALYSING

while(x>0)

{

//printf("checking up\n");

x--;

if(a[x][y]==a[i][j])

up++;

else

break;

}

x=i;

while(y<c)

{

//printf("checking right\n");

y++;

if(a[x][y]==a[i][j])

right++;

else

break;

}

//printf("%d %d",up,right);
if(up!=0 && up==right)
{
printf("Yes");
check=1;break;
}
}
if(check==1)
{break;}
}
if(check==0)
printf("No");
}

PRACTICE PROBLEM 2(24-1 to 31-1):COMPLEX NUMBERS

I had to forcefully format the output in the required manner.
For example it had to be +i and not +1i ..
So not much logic in this problem except for the calculation.
========================================================================


#include<stdio.h>
void add(int,int,int,int);
void sub(int,int,int,int);
void mul(int,int,int,int);
int main()
{
  int a,b,c,d;
  scanf("%d\n%d\n%d\n%d",&a,&b,&c,&d);
  add(a,b,c,d);
  sub(a,b,c,d);
  mul(a,b,c,d);

  return 0;

}
void add(int a,int b,int c,int d)
{
  if(b+d==1)
  printf("%d+i\n",a+c);
  else if(b+d==-1)
  printf("%d-i\n",a+c);
  else if(b+d>=0)
  printf("%d+%di\n",a+c,b+d);
  else
  printf("%d%di\n",a+c,b+d);
}
void sub(int a,int b,int c,int d)
{
  if(b-d==1)
  printf("%d+i",a-c);
  else if(b-d==-1)
  printf("%d-i",a-c);
  else if(b-d>=0)
  printf("%d+%di\n",a-c,b-d);
  else
  printf("%d%di\n",a-c,b-d);
}
void mul(int a,int b,int c,int d)
{
  if(a*d+b*c==1)
  printf("%d+i",a*c-b*d);
  else if(a*d+b*c==-1)
  printf("%d-i",a*c-b*d);
  else if(a*d+b*c>=0)
  printf("%d+%di",a*c-b*d,a*d+b*c);
  else
  printf("%d%di",a*c-b*d,a*d+b*c);

}

PRACTICE PROBLEM 2 -(24-1 to 31-1) : SINGULAR TO PLURAL

#include<stdio.h>
#include<string.h>
int main()
{

char s[100];
char p[100];
scanf("%s",s);
int l=strlen(s);
char last=s[l-1];
char last_two[2];
last_two[0]=s[l-2];
last_two[1]=s[l-1];
int i;
for(i = 0; s[i]; i++){
    s[i] = tolower(s[i]);
    }
strcpy(p,s);
if(strcmp(last_two,"ch")==0 || strcmp(last_two,"sh")==0 || last=='s')
{
p[l]='e';
p[l+1]='s';
p[l+2]='\0';
    }
   
else if(last=='y')
{
p[l-1]='i';
p[l]='e';
p[l+1]='s';
p[l+2]='\0';
    }
    else
    {
    p[l]='s';
}
printf("%s %s",s,p);
return 0;
}

PRACTICE PROBLEMS 2 (24-1 to 31-1) : CIRCULAR PRIMES

Please do not blindly copy/paste.Try understanding it.
For a detailed explaination :VIDEO HERE
Please let me know if i should continue making such videos where in i explain the solution.
---------------------------------------------------------------------------------------------------------------
#include<stdio.h>
#include<math.h>
int len(int);
int prime(int);
void main()
{
int N;
int i;
scanf("%d",&N);
int r=len(N);
int p=0;
for(i=1;i<=r;i++)
{
int num=N;
int j;
int le=len(N);
for(j=0;j<i;j++)
{
int rem=num%10;
num=(num/10)+(rem*pow(10,le-1));
}
int result=prime(num);
if(result==1)
p++;
}
if(p==r)
printf("Circular prime");
else
printf("Not circular prime");
}
int len(int a)
{
int l=0;
while(a>0)
{
l++;
a/=10;
}
return l;
}
int prime(int n)
{
int c=1;
int i;
for(i=2;i<n;i++)
{
if(n%i==0)
{
c=0;
break;
}
}
return c;
}

PRACTICE PROBLEM 1 (20-1 to 27-1) : SPEED OF SOUND

#include<stdio.h>
#include<math.h>
void main()
{
int t;
scanf("%d",&t);
printf("%.2f",1086*sqrt(((5*t)+297.0)/247.0));
}

PRACTICE PROBLEM 1 (20-1 to 27-1) : EMISSION STANDARDS

#include<stdio.h>
void main()
{
int P,O;
float N;
scanf("%d",&P);
scanf("%f",&N);
scanf("%d",&O);
switch(P)
{
case 1:if(O<=50000)
{
if(N<=3.4)
{
printf("Emission do not exceed permitted level of 3.4 g/mile");
}
else
{
printf("Emission exceed permitted level of 3.4 g/mile");
}
}
else
{
if(N<=1)
{
printf("Emission do not exceed permitted level of 1 g/mile");
}
else
{
printf("Emission exceed permitted level of 1 g/mile");
}
}
break;
case 2:if(O<=50000)
{
if(N<=0.31)
{
printf("Emission do not exceed permitted level of 0.31 g/mile");
}
else
{
printf("Emission exceed permitted level of 0.31 g/mile");
}
}
else
{
if(N<=0.39)
{
printf("Emission do not exceed permitted level of 0.39 g/mile");
}
else
{
printf("Emission exceed permitted level of 0.39 g/mile");
}
}
break;
case 3:if(O<=50000)
{
if(N<=0.4)
{
printf("Emission do not exceed permitted level of 0.4 g/mile");
}
else
{
printf("Emission exceed permitted level of 0.4 g/mile");
}
}
else
{
if(N<=0.5)
{
printf("Emission do not exceed permitted level of 1.0 g/mile");
}
else
{
printf("Emission exceed permitted level of 1.0 g/mile");
}
}
break;
case 4:if(O<=50000)
{
if(N<=0.25)
{
printf("Emission do not exceed permitted level of 0.25 g/mile");
}
else
{
printf("Emission exceed permitted level of 0.25 g/mile");
}
}
else
{
if(N<=0.31)
{
printf("Emission do not exceed permitted level of 0.31 g/mile");
}
else
{
printf("Emission exceed permitted level of 0.31 g/mile");
}
}
break;
}
}

PRACTICE PROBLEM 1 (20-1 to 27-1) : BAKING A BREAD

#include<stdio.h>
void main()
{
float time=0.0;
char b,s,t;
scanf("%c\n%c\n%c",&b,&s,&t);
if(b=='w')
{
time=time+6782;
if(t=='a')
{
time=time+9000;
}

}
else
{
time=8582;
if(t=='a')
{
time=time+8400;
}
}
if(s=='d')
{
time=time+(time*0.5);
}
printf("%.0f",time);

}
/*P.S.:Use a blank space instead of "\n" in input console if skillrack shows an error indicating "use standard input console"*/

Practice Problem 1 (20-1 to 27-1) : SPEED CONVERSION

#include<stdio.h>
#include<math.h>
void main()
{
int m;
float s;
scanf("%d",&m);
scanf("%f",&s);
int time;
time=m*60;
time+=(int)(s+0.5);
float fps=5280.0/time;
fps=roundf(fps*100)/100;
float mps=1609.34/time;
mps=roundf(mps*100)/100;
printf("%.2f fps\n",fps);
printf("%.2f mps",mps);
}

Practice Problem 1 (20-1 to 27-1) : WAGE

#include <stdio.h>
#include<math.h>
void main()
{
    int I,R,N;
    scanf("%d %d %d",&I,&R,&N);
    float G=0.0;
    if(N>40)
    {
        G=40*R+(N-40)*R*1.5;
    }
    else
    {
        G=R*N;
    }
    G=G-G*0.03625;
    G=roundf(G*100)/100;
    printf("%.2f",G);
 
}

SO IT BEGINS...

Practice problems for the course CSE1002 :Problem Solving with Object Oriented Programming have been uploaded on skillrack.com

Though these five simple problems have to be solved in C, the focus will migrate towards C++ further on in the course.

Best Of Luck to all for the new Semester .

And better late than never "Have A Very Prosperous Year"

-Karthik.